# How to do multiple operations on Bitsy 4.2

I came cross with the limitation of using conditional dialog's syntax as I cannot do multiple operations or like

- a == 1 and b == 2
- a + b + c == 2
- a = a + 1
- a + b * 2 < c

In this game, player has to find 1 lighter, 3 combs and 3 rings respectively in order to get the price. On each progress, buyer has to say different sentences. So, here is my conditions.

**<<Lua>>**

if lighter == 1 and comb == 3 and ring == 3 then

temp = 3

elseif lighter == 1 and comb == 3 then

temp = 2

elseif lighter == 1 then

temp = 1

else

temp = 0

end

**<<Bitsy Script>>**

{

- 1 == {item "lighter"} ?

{temp = 1}

- else ?

{temp = 0}

}{

- 1 == temp ?

{

- 3 == {item "comb"} ?

{temp = 2}

}

}{

- 2 == temp ?

{

- 3 == {item "ring"} ?

{temp = 3}

}

}{

- 0 == temp ?

Hello, I buy {wvy}Bric-A-Brac{wvy}.

But I need {rbw}a lighter{rbw} first.

- 1 == temp ?

{wvy}Thanks for the lighter!{wvy}

Could you find {rbw}3 combs{rbw} for me?

- 2 == temp ?

{wvy}Thanks for the combs and the lighter!{wvy}

Now find {rbw}3 rings{rbw}.

- 3 == temp ?

{wvy}Thanks for the rings, combs and lighter!{wvy}

(He gave you {rbw}$1{rbw})

}

**<<Shorter Version>**

{

- 1 == {item "lighter"} ?

{temp = 1}

- else ?

Hello, I buy {wvy}Bric-A-Brac{wvy}.

But I need {rbw}a lighter{rbw} first.

Find it and bring it back to me.

}{

- 1 == temp ?

{

- 3 == {item "comb"} ?

{temp = 2}

- else ?

{wvy}Thanks for the lighter!{wvy}

Could you find {rbw}3 combs{rbw} for me?

}

}{

- 2 == temp ?

{

- 3 == {item "ring"} ?

{wvy}Thanks for the rings, combs and lighter!{wvy}

(He gave you {rbw}$1{rbw})

- else ?

{wvy}Thanks for the combs and the lighter!{wvy}

Now find {rbw}3 rings{rbw}.

}

}

## Files

**index.html.zip**29 kB

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